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-24=0.04x^2-4x
We move all terms to the left:
-24-(0.04x^2-4x)=0
We get rid of parentheses
-0.04x^2+4x-24=0
a = -0.04; b = 4; c = -24;
Δ = b2-4ac
Δ = 42-4·(-0.04)·(-24)
Δ = 12.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-\sqrt{12.16}}{2*-0.04}=\frac{-4-\sqrt{12.16}}{-0.08} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+\sqrt{12.16}}{2*-0.04}=\frac{-4+\sqrt{12.16}}{-0.08} $
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